3(x-11)+5=2(x-2)+x-20

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Solution for 3(x-11)+5=2(x-2)+x-20 equation: 


Simplifying
3(x + -11) + 5 = 2(x + -2) + x + -20

Reorder the terms:
3(-11 + x) + 5 = 2(x + -2) + x + -20
(-11 * 3 + x * 3) + 5 = 2(x + -2) + x + -20
(-33 + 3x) + 5 = 2(x + -2) + x + -20

Reorder the terms:
-33 + 5 + 3x = 2(x + -2) + x + -20

Combine like terms: -33 + 5 = -28
-28 + 3x = 2(x + -2) + x + -20

Reorder the terms:
-28 + 3x = 2(-2 + x) + x + -20
-28 + 3x = (-2 * 2 + x * 2) + x + -20
-28 + 3x = (-4 + 2x) + x + -20

Reorder the terms:
-28 + 3x = -4 + -20 + 2x + x

Combine like terms: -4 + -20 = -24
-28 + 3x = -24 + 2x + x

Combine like terms: 2x + x = 3x
-28 + 3x = -24 + 3x

Add '-3x' to each side of the equation.
-28 + 3x + -3x = -24 + 3x + -3x

Combine like terms: 3x + -3x = 0
-28 + 0 = -24 + 3x + -3x
-28 = -24 + 3x + -3x

Combine like terms: 3x + -3x = 0
-28 = -24 + 0
-28 = -24

Solving
-28 = -24

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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