3(x-15)+(16)=6(x-1)-4x-1

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Solution for 3(x-15)+(16)=6(x-1)-4x-1 equation:



3(x-15)+(16)=6(x-1)-4x-1
We move all terms to the left:
3(x-15)+(16)-(6(x-1)-4x-1)=0
We multiply parentheses
3x-(6(x-1)-4x-1)-45+16=0
We calculate terms in parentheses: -(6(x-1)-4x-1), so:
6(x-1)-4x-1
We add all the numbers together, and all the variables
-4x+6(x-1)-1
We multiply parentheses
-4x+6x-6-1
We add all the numbers together, and all the variables
2x-7
Back to the equation:
-(2x-7)
We add all the numbers together, and all the variables
3x-(2x-7)-29=0
We get rid of parentheses
3x-2x+7-29=0
We add all the numbers together, and all the variables
x-22=0
We move all terms containing x to the left, all other terms to the right
x=22

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