3(x-2(3x-4))+15=5-(2x-(3+x))-11

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Solution for 3(x-2(3x-4))+15=5-(2x-(3+x))-11 equation: 



3(x-2(3x-4))+15=5-(2x-(3+x))-11

We move all terms to the left:

3(x-2(3x-4))+15-(5-(2x-(3+x))-11)=0

We add all the numbers together, and all the variables

3(x-2(3x-4))-(5-(2x-(x+3))-11)+15=0



We calculate terms in parentheses: -(5-(2x-(x+3))-11), so:

5-(2x-(x+3))-11

determiningTheFunctionDomain
-(2x-(x+3))+5-11

We add all the numbers together, and all the variables

-(2x-(x+3))-6



We calculate terms in parentheses: -(2x-(x+3)), so:

2x-(x+3)

We get rid of parentheses

2x-x-3

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

-x+3-6

We add all the numbers together, and all the variables

-1x-3

Back to the equation:

-(-1x-3)



We get rid of parentheses

3(x-2(3x-4))+1x+3+15=0

We add all the numbers together, and all the variables

x+3(x-2(3x-4))+18=0

We move all terms containing x to the left, all other terms to the right

x+3(x-2(3x-4))=-18

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