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3(x-2(3x-4))+15=5-(2x-(3+x))-11
We move all terms to the left:
3(x-2(3x-4))+15-(5-(2x-(3+x))-11)=0
We add all the numbers together, and all the variables
3(x-2(3x-4))-(5-(2x-(x+3))-11)+15=0
We calculate terms in parentheses: -(5-(2x-(x+3))-11), so:We get rid of parentheses
5-(2x-(x+3))-11
determiningTheFunctionDomain -(2x-(x+3))+5-11
We add all the numbers together, and all the variables
-(2x-(x+3))-6
We calculate terms in parentheses: -(2x-(x+3)), so:We get rid of parentheses
2x-(x+3)
We get rid of parentheses
2x-x-3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
-x+3-6
We add all the numbers together, and all the variables
-1x-3
Back to the equation:
-(-1x-3)
3(x-2(3x-4))+1x+3+15=0
We add all the numbers together, and all the variables
x+3(x-2(3x-4))+18=0
We move all terms containing x to the left, all other terms to the right
x+3(x-2(3x-4))=-18
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