3(x-2)+(2-x)=16

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Solution for 3(x-2)+(2-x)=16 equation: 



3(x-2)+(2-x)=16

We move all terms to the left:

3(x-2)+(2-x)-(16)=0

We add all the numbers together, and all the variables

3(x-2)+(-1x+2)-16=0

We multiply parentheses

3x+(-1x+2)-6-16=0

We get rid of parentheses

3x-1x+2-6-16=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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