3(x-2)+(4y-5)=-12

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Solution for 3(x-2)+(4y-5)=-12 equation:


Simplifying
3(x + -2) + (4y + -5) = -12

Reorder the terms:
3(-2 + x) + (4y + -5) = -12
(-2 * 3 + x * 3) + (4y + -5) = -12
(-6 + 3x) + (4y + -5) = -12

Reorder the terms:
-6 + 3x + (-5 + 4y) = -12

Remove parenthesis around (-5 + 4y)
-6 + 3x + -5 + 4y = -12

Reorder the terms:
-6 + -5 + 3x + 4y = -12

Combine like terms: -6 + -5 = -11
-11 + 3x + 4y = -12

Solving
-11 + 3x + 4y = -12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 3x + 11 + 4y = -12 + 11

Reorder the terms:
-11 + 11 + 3x + 4y = -12 + 11

Combine like terms: -11 + 11 = 0
0 + 3x + 4y = -12 + 11
3x + 4y = -12 + 11

Combine like terms: -12 + 11 = -1
3x + 4y = -1

Add '-4y' to each side of the equation.
3x + 4y + -4y = -1 + -4y

Combine like terms: 4y + -4y = 0
3x + 0 = -1 + -4y
3x = -1 + -4y

Divide each side by '3'.
x = -0.3333333333 + -1.333333333y

Simplifying
x = -0.3333333333 + -1.333333333y

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