3(x-2)+10=2(x-5)

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Solution for 3(x-2)+10=2(x-5) equation: 



3(x-2)+10=2(x-5)

We move all terms to the left:

3(x-2)+10-(2(x-5))=0

We multiply parentheses

3x-(2(x-5))-6+10=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

3x-(2x-10)+4=0

We get rid of parentheses

3x-2x+10+4=0

We add all the numbers together, and all the variables

x+14=0

We move all terms containing x to the left, all other terms to the right

x=-14

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