3(x-2)+11=5(x-3)+5

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Solution for 3(x-2)+11=5(x-3)+5 equation: 



3(x-2)+11=5(x-3)+5

We move all terms to the left:

3(x-2)+11-(5(x-3)+5)=0

We multiply parentheses

3x-(5(x-3)+5)-6+11=0



We calculate terms in parentheses: -(5(x-3)+5), so:

5(x-3)+5

We multiply parentheses

5x-15+5

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

3x-(5x-10)+5=0

We get rid of parentheses

3x-5x+10+5=0

We add all the numbers together, and all the variables

-2x+15=0

We move all terms containing x to the left, all other terms to the right

-2x=-15

x=-15/-2

x=7+1/2

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