3(x-2)+16=x+3(5+x)

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Solution for 3(x-2)+16=x+3(5+x) equation: 



3(x-2)+16=x+3(5+x)

We move all terms to the left:

3(x-2)+16-(x+3(5+x))=0

We add all the numbers together, and all the variables

3(x-2)-(x+3(x+5))+16=0

We multiply parentheses

3x-(x+3(x+5))-6+16=0



We calculate terms in parentheses: -(x+3(x+5)), so:

x+3(x+5)

We multiply parentheses

x+3x+15

We add all the numbers together, and all the variables

4x+15

Back to the equation:

-(4x+15)



We add all the numbers together, and all the variables

3x-(4x+15)+10=0

We get rid of parentheses

3x-4x-15+10=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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