3(x-2)+18=24-2(x+1)

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Solution for 3(x-2)+18=24-2(x+1) equation: 



3(x-2)+18=24-2(x+1)

We move all terms to the left:

3(x-2)+18-(24-2(x+1))=0

We multiply parentheses

3x-(24-2(x+1))-6+18=0



We calculate terms in parentheses: -(24-2(x+1)), so:

24-2(x+1)

determiningTheFunctionDomain
-2(x+1)+24

We multiply parentheses

-2x-2+24

We add all the numbers together, and all the variables

-2x+22

Back to the equation:

-(-2x+22)



We add all the numbers together, and all the variables

3x-(-2x+22)+12=0

We get rid of parentheses

3x+2x-22+12=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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