3(x-2)+1=(2(x-4)+x+13

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Solution for 3(x-2)+1=(2(x-4)+x+13 equation: 



3(x-2)+1=(2(x-4)+x+13

We move all terms to the left:

3(x-2)+1-((2(x-4)+x+13)=0

We multiply parentheses

3x-((2(x-4)+x+13)+1-6=0

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