3(x-2)+1=(3x+2)-7

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Solution for 3(x-2)+1=(3x+2)-7 equation: 



3(x-2)+1=(3x+2)-7

We move all terms to the left:

3(x-2)+1-((3x+2)-7)=0

We multiply parentheses

3x-((3x+2)-7)-6+1=0



We calculate terms in parentheses: -((3x+2)-7), so:

(3x+2)-7

We get rid of parentheses

3x+2-7

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

3x-(3x-5)-5=0

We get rid of parentheses

3x-3x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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