3(x-2)+1=-4(x+2)

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Solution for 3(x-2)+1=-4(x+2) equation: 



3(x-2)+1=-4(x+2)

We move all terms to the left:

3(x-2)+1-(-4(x+2))=0

We multiply parentheses

3x-(-4(x+2))-6+1=0



We calculate terms in parentheses: -(-4(x+2)), so:

-4(x+2)

We multiply parentheses

-4x-8

Back to the equation:

-(-4x-8)



We add all the numbers together, and all the variables

3x-(-4x-8)-5=0

We get rid of parentheses

3x+4x+8-5=0

We add all the numbers together, and all the variables

7x+3=0

We move all terms containing x to the left, all other terms to the right

7x=-3

x=-3/7

x=-3/7

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