3(x-2)+1=1x+2(x+2)

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Solution for 3(x-2)+1=1x+2(x+2) equation:


Simplifying
3(x + -2) + 1 = 1x + 2(x + 2)

Reorder the terms:
3(-2 + x) + 1 = 1x + 2(x + 2)
(-2 * 3 + x * 3) + 1 = 1x + 2(x + 2)
(-6 + 3x) + 1 = 1x + 2(x + 2)

Reorder the terms:
-6 + 1 + 3x = 1x + 2(x + 2)

Combine like terms: -6 + 1 = -5
-5 + 3x = 1x + 2(x + 2)

Reorder the terms:
-5 + 3x = 1x + 2(2 + x)
-5 + 3x = 1x + (2 * 2 + x * 2)
-5 + 3x = 1x + (4 + 2x)

Reorder the terms:
-5 + 3x = 4 + 1x + 2x

Combine like terms: 1x + 2x = 3x
-5 + 3x = 4 + 3x

Add '-3x' to each side of the equation.
-5 + 3x + -3x = 4 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 + 0 = 4 + 3x + -3x
-5 = 4 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 = 4 + 0
-5 = 4

Solving
-5 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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