3(x-2)+1=2(2x-4)+x+13

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Solution for 3(x-2)+1=2(2x-4)+x+13 equation: 



3(x-2)+1=2(2x-4)+x+13

We move all terms to the left:

3(x-2)+1-(2(2x-4)+x+13)=0

We multiply parentheses

3x-(2(2x-4)+x+13)-6+1=0



We calculate terms in parentheses: -(2(2x-4)+x+13), so:

2(2x-4)+x+13

We add all the numbers together, and all the variables

x+2(2x-4)+13

We multiply parentheses

x+4x-8+13

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

3x-(5x+5)-5=0

We get rid of parentheses

3x-5x-5-5=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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