3(x-2)+1=2(x-3)+(x+1)

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Solution for 3(x-2)+1=2(x-3)+(x+1) equation:


Simplifying
3(x + -2) + 1 = 2(x + -3) + (x + 1)

Reorder the terms:
3(-2 + x) + 1 = 2(x + -3) + (x + 1)
(-2 * 3 + x * 3) + 1 = 2(x + -3) + (x + 1)
(-6 + 3x) + 1 = 2(x + -3) + (x + 1)

Reorder the terms:
-6 + 1 + 3x = 2(x + -3) + (x + 1)

Combine like terms: -6 + 1 = -5
-5 + 3x = 2(x + -3) + (x + 1)

Reorder the terms:
-5 + 3x = 2(-3 + x) + (x + 1)
-5 + 3x = (-3 * 2 + x * 2) + (x + 1)
-5 + 3x = (-6 + 2x) + (x + 1)

Reorder the terms:
-5 + 3x = -6 + 2x + (1 + x)

Remove parenthesis around (1 + x)
-5 + 3x = -6 + 2x + 1 + x

Reorder the terms:
-5 + 3x = -6 + 1 + 2x + x

Combine like terms: -6 + 1 = -5
-5 + 3x = -5 + 2x + x

Combine like terms: 2x + x = 3x
-5 + 3x = -5 + 3x

Add '5' to each side of the equation.
-5 + 5 + 3x = -5 + 5 + 3x

Combine like terms: -5 + 5 = 0
0 + 3x = -5 + 5 + 3x
3x = -5 + 5 + 3x

Combine like terms: -5 + 5 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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