3(x-2)+1=2(x-4)+x+13

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Solution for 3(x-2)+1=2(x-4)+x+13 equation: 


Simplifying
3(x + -2) + 1 = 2(x + -4) + x + 13

Reorder the terms:
3(-2 + x) + 1 = 2(x + -4) + x + 13
(-2 * 3 + x * 3) + 1 = 2(x + -4) + x + 13
(-6 + 3x) + 1 = 2(x + -4) + x + 13

Reorder the terms:
-6 + 1 + 3x = 2(x + -4) + x + 13

Combine like terms: -6 + 1 = -5
-5 + 3x = 2(x + -4) + x + 13

Reorder the terms:
-5 + 3x = 2(-4 + x) + x + 13
-5 + 3x = (-4 * 2 + x * 2) + x + 13
-5 + 3x = (-8 + 2x) + x + 13

Reorder the terms:
-5 + 3x = -8 + 13 + 2x + x

Combine like terms: -8 + 13 = 5
-5 + 3x = 5 + 2x + x

Combine like terms: 2x + x = 3x
-5 + 3x = 5 + 3x

Add '-3x' to each side of the equation.
-5 + 3x + -3x = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 + 0 = 5 + 3x + -3x
-5 = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 = 5 + 0
-5 = 5

Solving
-5 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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