3(x-2)+1=2(x-4)+x+22

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Solution for 3(x-2)+1=2(x-4)+x+22 equation: 



3(x-2)+1=2(x-4)+x+22

We move all terms to the left:

3(x-2)+1-(2(x-4)+x+22)=0

We multiply parentheses

3x-(2(x-4)+x+22)-6+1=0



We calculate terms in parentheses: -(2(x-4)+x+22), so:

2(x-4)+x+22

We add all the numbers together, and all the variables

x+2(x-4)+22

We multiply parentheses

x+2x-8+22

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We add all the numbers together, and all the variables

3x-(3x+14)-5=0

We get rid of parentheses

3x-3x-14-5=0

We add all the numbers together, and all the variables

-19!=0

There is no solution for this equation

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