3(x-2)+1=2(x-4)=x=13

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Solution for 3(x-2)+1=2(x-4)=x=13 equation: 



3(x-2)+1=2(x-4)=x=13

We move all terms to the left:

3(x-2)+1-(2(x-4))=0

We multiply parentheses

3x-(2(x-4))-6+1=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

3x-(2x-8)-5=0

We get rid of parentheses

3x-2x+8-5=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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