3(x-2)+1=2(x-4+X+13

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Solution for 3(x-2)+1=2(x-4+X+13 equation: 



3(x-2)+1=2(x-4+x+13

We move all terms to the left:

3(x-2)+1-(2(x-4+x+13)=0

We add all the numbers together, and all the variables

3(x-2)-(2(2x+9)+1=0

We multiply parentheses

3x-(2(2x+9)+1-6=0

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