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3(x-2)+1=5(x-1)+2x
We move all terms to the left:
3(x-2)+1-(5(x-1)+2x)=0
We multiply parentheses
3x-(5(x-1)+2x)-6+1=0
We calculate terms in parentheses: -(5(x-1)+2x), so:We add all the numbers together, and all the variables
5(x-1)+2x
We add all the numbers together, and all the variables
2x+5(x-1)
We multiply parentheses
2x+5x-5
We add all the numbers together, and all the variables
7x-5
Back to the equation:
-(7x-5)
3x-(7x-5)-5=0
We get rid of parentheses
3x-7x+5-5=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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