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3(x-2)+1=5x-2(5+x)
We move all terms to the left:
3(x-2)+1-(5x-2(5+x))=0
We add all the numbers together, and all the variables
3(x-2)-(5x-2(x+5))+1=0
We multiply parentheses
3x-(5x-2(x+5))-6+1=0
We calculate terms in parentheses: -(5x-2(x+5)), so:We add all the numbers together, and all the variables
5x-2(x+5)
We multiply parentheses
5x-2x-10
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
3x-(3x-10)-5=0
We get rid of parentheses
3x-3x+10-5=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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