3(x-2)+2(x+1)=27

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Solution for 3(x-2)+2(x+1)=27 equation: 



3(x-2)+2(x+1)=27

We move all terms to the left:

3(x-2)+2(x+1)-(27)=0

We multiply parentheses

3x+2x-6+2-27=0

We add all the numbers together, and all the variables

5x-31=0

We move all terms containing x to the left, all other terms to the right

5x=31

x=31/5

x=6+1/5

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