3(x-2)+2(x+5)=5(x+1)+1

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Solution for 3(x-2)+2(x+5)=5(x+1)+1 equation: 


Simplifying
3(x + -2) + 2(x + 5) = 5(x + 1) + 1

Reorder the terms:
3(-2 + x) + 2(x + 5) = 5(x + 1) + 1
(-2 * 3 + x * 3) + 2(x + 5) = 5(x + 1) + 1
(-6 + 3x) + 2(x + 5) = 5(x + 1) + 1

Reorder the terms:
-6 + 3x + 2(5 + x) = 5(x + 1) + 1
-6 + 3x + (5 * 2 + x * 2) = 5(x + 1) + 1
-6 + 3x + (10 + 2x) = 5(x + 1) + 1

Reorder the terms:
-6 + 10 + 3x + 2x = 5(x + 1) + 1

Combine like terms: -6 + 10 = 4
4 + 3x + 2x = 5(x + 1) + 1

Combine like terms: 3x + 2x = 5x
4 + 5x = 5(x + 1) + 1

Reorder the terms:
4 + 5x = 5(1 + x) + 1
4 + 5x = (1 * 5 + x * 5) + 1
4 + 5x = (5 + 5x) + 1

Reorder the terms:
4 + 5x = 5 + 1 + 5x

Combine like terms: 5 + 1 = 6
4 + 5x = 6 + 5x

Add '-5x' to each side of the equation.
4 + 5x + -5x = 6 + 5x + -5x

Combine like terms: 5x + -5x = 0
4 + 0 = 6 + 5x + -5x
4 = 6 + 5x + -5x

Combine like terms: 5x + -5x = 0
4 = 6 + 0
4 = 6

Solving
4 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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