3(x-2)+2(x-3)-4(2x-1)+5(x-1)=27

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Solution for 3(x-2)+2(x-3)-4(2x-1)+5(x-1)=27 equation: 



3(x-2)+2(x-3)-4(2x-1)+5(x-1)=27

We move all terms to the left:

3(x-2)+2(x-3)-4(2x-1)+5(x-1)-(27)=0

We multiply parentheses

3x+2x-8x+5x-6-6+4-5-27=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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