3(x-2)+2(x-3)=5(x-1)-7(x-4)

Solution for 3(x-2)+2(x-3)=5(x-1)-7(x-4) equation:

3(x-2)+2(x-3)=5(x-1)-7(x-4)

We move all terms to the left:

3(x-2)+2(x-3)-(5(x-1)-7(x-4))=0

We multiply parentheses

3x+2x-(5(x-1)-7(x-4))-6-6=0


We calculate terms in parentheses: -(5(x-1)-7(x-4)), so:

5(x-1)-7(x-4)

We multiply parentheses

5x-7x-5+28

We add all the numbers together, and all the variables

-2x+23

Back to the equation:

-(-2x+23)


We add all the numbers together, and all the variables

5x-(-2x+23)-12=0

We get rid of parentheses

5x+2x-23-12=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5