3(x-2)+2(x-4)=6

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Solution for 3(x-2)+2(x-4)=6 equation:



3(x-2)+2(x-4)=6
We move all terms to the left:
3(x-2)+2(x-4)-(6)=0
We multiply parentheses
3x+2x-6-8-6=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4

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