3(x-2)+2(x-4)=6

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Solution for 3(x-2)+2(x-4)=6 equation: 



3(x-2)+2(x-4)=6

We move all terms to the left:

3(x-2)+2(x-4)-(6)=0

We multiply parentheses

3x+2x-6-8-6=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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