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3(x-2)+2(x-5)=9x
We move all terms to the left:
3(x-2)+2(x-5)-(9x)=0
We add all the numbers together, and all the variables
-9x+3(x-2)+2(x-5)=0
We multiply parentheses
-9x+3x+2x-6-10=0
We add all the numbers together, and all the variables
-4x-16=0
We move all terms containing x to the left, all other terms to the right
-4x=16
x=16/-4
x=-4
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