3(x-2)+2x=4x+12

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Solution for 3(x-2)+2x=4x+12 equation:



3(x-2)+2x=4x+12
We move all terms to the left:
3(x-2)+2x-(4x+12)=0
We add all the numbers together, and all the variables
2x+3(x-2)-(4x+12)=0
We multiply parentheses
2x+3x-(4x+12)-6=0
We get rid of parentheses
2x+3x-4x-12-6=0
We add all the numbers together, and all the variables
x-18=0
We move all terms containing x to the left, all other terms to the right
x=18

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