3(x-2)+2x=7(x+4)-38

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Solution for 3(x-2)+2x=7(x+4)-38 equation: 



3(x-2)+2x=7(x+4)-38

We move all terms to the left:

3(x-2)+2x-(7(x+4)-38)=0

We add all the numbers together, and all the variables

2x+3(x-2)-(7(x+4)-38)=0

We multiply parentheses

2x+3x-(7(x+4)-38)-6=0



We calculate terms in parentheses: -(7(x+4)-38), so:

7(x+4)-38

We multiply parentheses

7x+28-38

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We add all the numbers together, and all the variables

5x-(7x-10)-6=0

We get rid of parentheses

5x-7x+10-6=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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