3(x-2)+3(x+4)=23

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Solution for 3(x-2)+3(x+4)=23 equation: 



3(x-2)+3(x+4)=23

We move all terms to the left:

3(x-2)+3(x+4)-(23)=0

We multiply parentheses

3x+3x-6+12-23=0

We add all the numbers together, and all the variables

6x-17=0

We move all terms containing x to the left, all other terms to the right

6x=17

x=17/6

x=2+5/6

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