3(x-2)+3=4(x-1)+1

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Solution for 3(x-2)+3=4(x-1)+1 equation: 



3(x-2)+3=4(x-1)+1

We move all terms to the left:

3(x-2)+3-(4(x-1)+1)=0

We multiply parentheses

3x-(4(x-1)+1)-6+3=0



We calculate terms in parentheses: -(4(x-1)+1), so:

4(x-1)+1

We multiply parentheses

4x-4+1

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

3x-(4x-3)-3=0

We get rid of parentheses

3x-4x+3-3=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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