3(x-2)+4(2-6)=6(x-4)+8(2x+1)

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Solution for 3(x-2)+4(2-6)=6(x-4)+8(2x+1) equation: 



3(x-2)+4(2-6)=6(x-4)+8(2x+1)

We move all terms to the left:

3(x-2)+4(2-6)-(6(x-4)+8(2x+1))=0

We add all the numbers together, and all the variables

3(x-2)-(6(x-4)+8(2x+1))+4(-4)=0

We add all the numbers together, and all the variables

3(x-2)-(6(x-4)+8(2x+1))-16=0

We multiply parentheses

3x-(6(x-4)+8(2x+1))-6-16=0



We calculate terms in parentheses: -(6(x-4)+8(2x+1)), so:

6(x-4)+8(2x+1)

We multiply parentheses

6x+16x-24+8

We add all the numbers together, and all the variables

22x-16

Back to the equation:

-(22x-16)



We add all the numbers together, and all the variables

3x-(22x-16)-22=0

We get rid of parentheses

3x-22x+16-22=0

We add all the numbers together, and all the variables

-19x-6=0

We move all terms containing x to the left, all other terms to the right

-19x=6

x=6/-19

x=-6/19

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