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3(x-2)+4(2-x)=x+2(x+1
We move all terms to the left:
3(x-2)+4(2-x)-(x+2(x+1)=0
We add all the numbers together, and all the variables
3(x-2)+4(-1x+2)-(x+2(x+1)=0
We multiply parentheses
3x-4x-(x+2(x+1)-6+8=0
We add all the numbers together, and all the variables
-1x-(x+2(x+1)-6+8=0
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