3(x-2)+4(2-x)=x+2(x+1)2

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Solution for 3(x-2)+4(2-x)=x+2(x+1)2 equation: 



3(x-2)+4(2-x)=x+2(x+1)2

We move all terms to the left:

3(x-2)+4(2-x)-(x+2(x+1)2)=0

We add all the numbers together, and all the variables

3(x-2)+4(-1x+2)-(x+2(x+1)2)=0

We multiply parentheses

3x-4x-(x+2(x+1)2)-6+8=0



We calculate terms in parentheses: -(x+2(x+1)2), so:

x+2(x+1)2

We multiply parentheses

x+4x+4

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We add all the numbers together, and all the variables

-1x-(5x+4)+2=0

We get rid of parentheses

-1x-5x-4+2=0

We add all the numbers together, and all the variables

-6x-2=0

We move all terms containing x to the left, all other terms to the right

-6x=2

x=2/-6

x=-1/3

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