3(x-2)+4(2-x)=x+2(x-2)

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Solution for 3(x-2)+4(2-x)=x+2(x-2) equation: 



3(x-2)+4(2-x)=x+2(x-2)

We move all terms to the left:

3(x-2)+4(2-x)-(x+2(x-2))=0

We add all the numbers together, and all the variables

3(x-2)+4(-1x+2)-(x+2(x-2))=0

We multiply parentheses

3x-4x-(x+2(x-2))-6+8=0



We calculate terms in parentheses: -(x+2(x-2)), so:

x+2(x-2)

We multiply parentheses

x+2x-4

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

-1x-(3x-4)+2=0

We get rid of parentheses

-1x-3x+4+2=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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