3(x-2)+4(2x-6)=6(x-4)+(2x+1)

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Solution for 3(x-2)+4(2x-6)=6(x-4)+(2x+1) equation: 



3(x-2)+4(2x-6)=6(x-4)+(2x+1)

We move all terms to the left:

3(x-2)+4(2x-6)-(6(x-4)+(2x+1))=0

We multiply parentheses

3x+8x-(6(x-4)+(2x+1))-6-24=0



We calculate terms in parentheses: -(6(x-4)+(2x+1)), so:

6(x-4)+(2x+1)

We multiply parentheses

6x+(2x+1)-24

We get rid of parentheses

6x+2x+1-24

We add all the numbers together, and all the variables

8x-23

Back to the equation:

-(8x-23)



We add all the numbers together, and all the variables

11x-(8x-23)-30=0

We get rid of parentheses

11x-8x+23-30=0

We add all the numbers together, and all the variables

3x-7=0

We move all terms containing x to the left, all other terms to the right

3x=7

x=7/3

x=2+1/3

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