3(x-2)+4(2x-6)=6(x-4)+8(x-4)+8(2x+1)

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Solution for 3(x-2)+4(2x-6)=6(x-4)+8(x-4)+8(2x+1) equation: 



3(x-2)+4(2x-6)=6(x-4)+8(x-4)+8(2x+1)

We move all terms to the left:

3(x-2)+4(2x-6)-(6(x-4)+8(x-4)+8(2x+1))=0

We multiply parentheses

3x+8x-(6(x-4)+8(x-4)+8(2x+1))-6-24=0



We calculate terms in parentheses: -(6(x-4)+8(x-4)+8(2x+1)), so:

6(x-4)+8(x-4)+8(2x+1)

We multiply parentheses

6x+8x+16x-24-32+8

We add all the numbers together, and all the variables

30x-48

Back to the equation:

-(30x-48)



We add all the numbers together, and all the variables

11x-(30x-48)-30=0

We get rid of parentheses

11x-30x+48-30=0

We add all the numbers together, and all the variables

-19x+18=0

We move all terms containing x to the left, all other terms to the right

-19x=-18

x=-18/-19

x=18/19

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