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3(x-2)+4(2x-6)=6(x-4)=8(2x+1
We move all terms to the left:
3(x-2)+4(2x-6)-(6(x-4))=0
We multiply parentheses
3x+8x-(6(x-4))-6-24=0
We calculate terms in parentheses: -(6(x-4)), so:We add all the numbers together, and all the variables
6(x-4)
We multiply parentheses
6x-24
Back to the equation:
-(6x-24)
11x-(6x-24)-30=0
We get rid of parentheses
11x-6x+24-30=0
We add all the numbers together, and all the variables
5x-6=0
We move all terms containing x to the left, all other terms to the right
5x=6
x=6/5
x=1+1/5
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