3(x-2)+4(x+1)=12

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Solution for 3(x-2)+4(x+1)=12 equation:


Simplifying
3(x + -2) + 4(x + 1) = 12

Reorder the terms:
3(-2 + x) + 4(x + 1) = 12
(-2 * 3 + x * 3) + 4(x + 1) = 12
(-6 + 3x) + 4(x + 1) = 12

Reorder the terms:
-6 + 3x + 4(1 + x) = 12
-6 + 3x + (1 * 4 + x * 4) = 12
-6 + 3x + (4 + 4x) = 12

Reorder the terms:
-6 + 4 + 3x + 4x = 12

Combine like terms: -6 + 4 = -2
-2 + 3x + 4x = 12

Combine like terms: 3x + 4x = 7x
-2 + 7x = 12

Solving
-2 + 7x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 7x = 12 + 2

Combine like terms: -2 + 2 = 0
0 + 7x = 12 + 2
7x = 12 + 2

Combine like terms: 12 + 2 = 14
7x = 14

Divide each side by '7'.
x = 2

Simplifying
x = 2

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