3(x-2)+4(x+3)=6(x+1)

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Solution for 3(x-2)+4(x+3)=6(x+1) equation: 



3(x-2)+4(x+3)=6(x+1)

We move all terms to the left:

3(x-2)+4(x+3)-(6(x+1))=0

We multiply parentheses

3x+4x-(6(x+1))-6+12=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

7x-(6x+6)+6=0

We get rid of parentheses

7x-6x-6+6=0

We add all the numbers together, and all the variables

x=0

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