3(x-2)+4=12-5(x+1)

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Solution for 3(x-2)+4=12-5(x+1) equation: 



3(x-2)+4=12-5(x+1)

We move all terms to the left:

3(x-2)+4-(12-5(x+1))=0

We multiply parentheses

3x-(12-5(x+1))-6+4=0



We calculate terms in parentheses: -(12-5(x+1)), so:

12-5(x+1)

determiningTheFunctionDomain
-5(x+1)+12

We multiply parentheses

-5x-5+12

We add all the numbers together, and all the variables

-5x+7

Back to the equation:

-(-5x+7)



We add all the numbers together, and all the variables

3x-(-5x+7)-2=0

We get rid of parentheses

3x+5x-7-2=0

We add all the numbers together, and all the variables

8x-9=0

We move all terms containing x to the left, all other terms to the right

8x=9

x=9/8

x=1+1/8

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