3(x-2)+4=2(x+1)-6

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Solution for 3(x-2)+4=2(x+1)-6 equation: 



3(x-2)+4=2(x+1)-6

We move all terms to the left:

3(x-2)+4-(2(x+1)-6)=0

We multiply parentheses

3x-(2(x+1)-6)-6+4=0



We calculate terms in parentheses: -(2(x+1)-6), so:

2(x+1)-6

We multiply parentheses

2x+2-6

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

3x-(2x-4)-2=0

We get rid of parentheses

3x-2x+4-2=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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