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3(x-2)+4=2(x+4)-5
We move all terms to the left:
3(x-2)+4-(2(x+4)-5)=0
We multiply parentheses
3x-(2(x+4)-5)-6+4=0
We calculate terms in parentheses: -(2(x+4)-5), so:We add all the numbers together, and all the variables
2(x+4)-5
We multiply parentheses
2x+8-5
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
3x-(2x+3)-2=0
We get rid of parentheses
3x-2x-3-2=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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