3(x-2)+4=40(x,+1)

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Solution for 3(x-2)+4=40(x,+1) equation: 



3(x-2)+4=40(x.+1)

We move all terms to the left:

3(x-2)+4-(40(x.+1))=0

We multiply parentheses

3x-(40(x.+1))-6+4=0



We calculate terms in parentheses: -(40(x.+1)), so:

40(x.+1)

We multiply parentheses

40x+40

Back to the equation:

-(40x+40)



We add all the numbers together, and all the variables

3x-(40x+40)-2=0

We get rid of parentheses

3x-40x-40-2=0

We add all the numbers together, and all the variables

-37x-42=0

We move all terms containing x to the left, all other terms to the right

-37x=42

x=42/-37

x=-1+5/37

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