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3(x-2)+4x-5=7(x+1-6
We move all terms to the left:
3(x-2)+4x-5-(7(x+1-6)=0
We add all the numbers together, and all the variables
3(x-2)+4x-(7(x-5)-5=0
We add all the numbers together, and all the variables
4x+3(x-2)-(7(x-5)-5=0
We multiply parentheses
4x+3x-(7(x-5)-5-6=0
We add all the numbers together, and all the variables
7x-(7(x-5)-5-6=0
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