3(x-2)+4x=10(x-1)

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Solution for 3(x-2)+4x=10(x-1) equation:



3(x-2)+4x=10(x-1)
We move all terms to the left:
3(x-2)+4x-(10(x-1))=0
We add all the numbers together, and all the variables
4x+3(x-2)-(10(x-1))=0
We multiply parentheses
4x+3x-(10(x-1))-6=0
We calculate terms in parentheses: -(10(x-1)), so:
10(x-1)
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
We add all the numbers together, and all the variables
7x-(10x-10)-6=0
We get rid of parentheses
7x-10x+10-6=0
We add all the numbers together, and all the variables
-3x+4=0
We move all terms containing x to the left, all other terms to the right
-3x=-4
x=-4/-3
x=1+1/3

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