3(x-2)+4x=8(x+2)-10

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Solution for 3(x-2)+4x=8(x+2)-10 equation:



3(x-2)+4x=8(x+2)-10
We move all terms to the left:
3(x-2)+4x-(8(x+2)-10)=0
We add all the numbers together, and all the variables
4x+3(x-2)-(8(x+2)-10)=0
We multiply parentheses
4x+3x-(8(x+2)-10)-6=0
We calculate terms in parentheses: -(8(x+2)-10), so:
8(x+2)-10
We multiply parentheses
8x+16-10
We add all the numbers together, and all the variables
8x+6
Back to the equation:
-(8x+6)
We add all the numbers together, and all the variables
7x-(8x+6)-6=0
We get rid of parentheses
7x-8x-6-6=0
We add all the numbers together, and all the variables
-1x-12=0
We move all terms containing x to the left, all other terms to the right
-x=12
x=12/-1
x=-12

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