3(x-2)+5(2-x)=10

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Solution for 3(x-2)+5(2-x)=10 equation:



3(x-2)+5(2-x)=10
We move all terms to the left:
3(x-2)+5(2-x)-(10)=0
We add all the numbers together, and all the variables
3(x-2)+5(-1x+2)-10=0
We multiply parentheses
3x-5x-6+10-10=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3

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