3(x-2)+5=13+2(3x+5)

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Solution for 3(x-2)+5=13+2(3x+5) equation:



3(x-2)+5=13+2(3x+5)
We move all terms to the left:
3(x-2)+5-(13+2(3x+5))=0
We multiply parentheses
3x-(13+2(3x+5))-6+5=0
We calculate terms in parentheses: -(13+2(3x+5)), so:
13+2(3x+5)
determiningTheFunctionDomain 2(3x+5)+13
We multiply parentheses
6x+10+13
We add all the numbers together, and all the variables
6x+23
Back to the equation:
-(6x+23)
We add all the numbers together, and all the variables
3x-(6x+23)-1=0
We get rid of parentheses
3x-6x-23-1=0
We add all the numbers together, and all the variables
-3x-24=0
We move all terms containing x to the left, all other terms to the right
-3x=24
x=24/-3
x=-8

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