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3(x-2)+5=2(3x-2)
We move all terms to the left:
3(x-2)+5-(2(3x-2))=0
We multiply parentheses
3x-(2(3x-2))-6+5=0
We calculate terms in parentheses: -(2(3x-2)), so:We add all the numbers together, and all the variables
2(3x-2)
We multiply parentheses
6x-4
Back to the equation:
-(6x-4)
3x-(6x-4)-1=0
We get rid of parentheses
3x-6x+4-1=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1
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